二‧情報虛實位能差(泡沫)672Please respect copyright.PENANA9whncFbdHy
672Please respect copyright.PENANAIOix1klzcD
錯誤情報與真實情報,會在觀測者與被觀測物之間產生能量差,系統中的量子會從高處往低處流動,捕捉其運動軌跡就能推導未知事件。672Please respect copyright.PENANAtaNxK5VgFC
672Please respect copyright.PENANAfQhyBRwCj7
例:672Please respect copyright.PENANAzqWskHJSxN
封閉的箱子中有一顆蘋果,設總熵為1。672Please respect copyright.PENANAK6INaon7u7
觀測者被告知情報:箱子中有一顆蘋果,總熵為1。672Please respect copyright.PENANAPGWHxFUQ1g
開啟箱子,兩系統的總熵相等,因果收束前後沒有情報能量流動。672Please respect copyright.PENANAzWG25ybJK1
672Please respect copyright.PENANAy1gn1zRVBc
封閉的箱子中有一顆蘋果,設總熵為1。672Please respect copyright.PENANAdlSad4NfJf
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。672Please respect copyright.PENANAEAj51lFtih
開啟箱子,兩系統的總熵差1,因果收束前後有情報能量流動。672Please respect copyright.PENANAvCmDhLMR8g
672Please respect copyright.PENANAr9a87Y4T05
封閉的箱子中有一顆蘋果,設總熵為1。672Please respect copyright.PENANAlaSLbupMxi
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。672Please respect copyright.PENANAU72pJuEZiG
不開啟箱子,兩系統的總熵差1,此差異持續存在的狀態,專案內稱之為泡沫。672Please respect copyright.PENANAyR3iLN9x0j
672Please respect copyright.PENANAhsGr4t1rij
封閉的箱子中有一顆蘋果,設總熵為1。672Please respect copyright.PENANA0xauSWCjm7
100名觀測者被告知情報:箱子中有兩顆蘋果,總熵為2*100=200。672Please respect copyright.PENANA3IGzeS6vqw
不開啟箱子,兩系統的總熵差199,此差異持續存在的狀態,總共有199顆泡沫。672Please respect copyright.PENANAVau0UYjP5T
672Please respect copyright.PENANAu4eG61F6cA
根據第二定律,宇宙中的情報總熵必定趨向均衡。泡沫產生的混亂必定會分散至其他系統中。比如:多出來的那些「不存在的蘋果」導致價格下跌,果農賺得的能量因而減少。672Please respect copyright.PENANAQBlQb5QSqe
672Please respect copyright.PENANAPRNDKcQ4kp
定位、統計、歸納,得知所有粒子的運動狀態就能計算出未來的動向。觀察、分析、統整這些資訊,並導入演算機中的工作,本應交由AI電子腦擔任,但原初智叛亂後,現今局勢反對高性能AI生產,最合乎成本效益的解決方案就是人類頭腦。處理如此複雜的系統需要大量樣本,且必定會出現損壞,最好的方式就是使用Q型複製人。672Please respect copyright.PENANAXgJg7RWOCK
672Please respect copyright.PENANAbnbDrNuacb
(New)672Please respect copyright.PENANAvkM49co7dZ
新展望:加入纏結粒子技術的精準推導法,下述。672Please respect copyright.PENANAOI56RXFv8u
672Please respect copyright.PENANAn0tigtRXGJ
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拉普拉斯演算機:情報泡沫儲存槽
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拉普拉斯演算機:情報泡沫儲存槽
Author:
LiCh 阿立
ISSUE #2
預知未來的方法:因果率演算理論模型(二)
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