二‧情報虛實位能差(泡沫)562Please respect copyright.PENANAy9N5ctlB3h
562Please respect copyright.PENANA8i0Ql3MZOG
錯誤情報與真實情報,會在觀測者與被觀測物之間產生能量差,系統中的量子會從高處往低處流動,捕捉其運動軌跡就能推導未知事件。562Please respect copyright.PENANAMTcGKte6md
562Please respect copyright.PENANAYS6cWCJLtk
例:562Please respect copyright.PENANAwWUZ4CIVnk
封閉的箱子中有一顆蘋果,設總熵為1。562Please respect copyright.PENANAF6MalGJN38
觀測者被告知情報:箱子中有一顆蘋果,總熵為1。562Please respect copyright.PENANAgHQd4Yq3Vq
開啟箱子,兩系統的總熵相等,因果收束前後沒有情報能量流動。562Please respect copyright.PENANAvPYgiwJNki
562Please respect copyright.PENANA4NoU0HD5j9
封閉的箱子中有一顆蘋果,設總熵為1。562Please respect copyright.PENANARHV4CH8j1j
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。562Please respect copyright.PENANAPxUY8EDJk5
開啟箱子,兩系統的總熵差1,因果收束前後有情報能量流動。562Please respect copyright.PENANA2cOjCQms3N
562Please respect copyright.PENANAx93yjIkF5P
封閉的箱子中有一顆蘋果,設總熵為1。562Please respect copyright.PENANAxrGXZ2TDoS
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。562Please respect copyright.PENANAzya1ZzEDl1
不開啟箱子,兩系統的總熵差1,此差異持續存在的狀態,專案內稱之為泡沫。562Please respect copyright.PENANA53jzWRMoyI
562Please respect copyright.PENANAcx4iGEwdtK
封閉的箱子中有一顆蘋果,設總熵為1。562Please respect copyright.PENANAxmABxFGYzE
100名觀測者被告知情報:箱子中有兩顆蘋果,總熵為2*100=200。562Please respect copyright.PENANAgIp3EVB9eq
不開啟箱子,兩系統的總熵差199,此差異持續存在的狀態,總共有199顆泡沫。562Please respect copyright.PENANAAHRiZzFBxc
562Please respect copyright.PENANALZK964pwfa
根據第二定律,宇宙中的情報總熵必定趨向均衡。泡沫產生的混亂必定會分散至其他系統中。比如:多出來的那些「不存在的蘋果」導致價格下跌,果農賺得的能量因而減少。562Please respect copyright.PENANAcWNqTNR0KA
562Please respect copyright.PENANAu52NST9QVE
定位、統計、歸納,得知所有粒子的運動狀態就能計算出未來的動向。觀察、分析、統整這些資訊,並導入演算機中的工作,本應交由AI電子腦擔任,但原初智叛亂後,現今局勢反對高性能AI生產,最合乎成本效益的解決方案就是人類頭腦。處理如此複雜的系統需要大量樣本,且必定會出現損壞,最好的方式就是使用Q型複製人。562Please respect copyright.PENANAGQjsNIWWGh
562Please respect copyright.PENANAKHLjuSZkeo
(New)562Please respect copyright.PENANAmbchSZTOk1
新展望:加入纏結粒子技術的精準推導法,下述。562Please respect copyright.PENANAhTnHvdEMIZ
562Please respect copyright.PENANAoQwUURoSfU
arrow_back
拉普拉斯演算機:情報泡沫儲存槽
more_vert
-
info_outline Info
-
toc Table of Contents
-
share Share
-
format_color_text Display Settings
-
exposure_plus_1 Recommend
-
Sponsor
-
report_problem Report
-
account_circle Login
Search stories, writers or societies
Continue ReadingClear All
What Others Are ReadingRefresh
X
Never miss what's happening on Penana!
拉普拉斯演算機:情報泡沫儲存槽
Author:
LiCh 阿立
ISSUE #2
預知未來的方法:因果率演算理論模型(二)
LIKES 0
READS 558
BOOKMARKS 3
campaign
Request update 0
Sponsor
Suggest Edits
Login with Facebook
or Sign up/Login to comment or bookmark! Click to load the next chapter
x
will be deducted
will be deducted Your current coin balance: 0Click to buy coins
A recurring charge will be deducted , unless you decide to cancel. You can cancel your subscription at any time.
You can also pay with credit card
X
After each update request, the author will receive a notification!
smartphone100
→ Request update
X
Sponsor again
Click to login
Login first to show your name as a sponsor.
Thank you for supporting the story! :)
Please Login first.
×
Write down what you like about the story
×
Reading Theme:
Font Size:
Line Spacing:
Paragraph Spacing:
Load the next issue automatically
Reset to default
×
People Who Like This
x
Before You Publish
Please ensure your story does not contain illegal, hateful, inciting, or violence-promoting content, or any infringing, plagiarized, or spam material, and that it complies with Penana’s Terms of Use.
Penana reserves the right to remove any content that violates these rules or causes legal or community risk, and to suspend or terminate related accounts.
